HI,
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import java.awt.Image;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.TimeZone;
import javax.imageio.ImageIO;
import javax.swing.ImageIcon;
import javax.swing.JFrame;
import javax.swing.JLabel;
import oauth.signpost.OAuthConsumer;
import oauth.signpost.commonshttp.CommonsHttpOAuthConsumer;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONObject;
public class TwitterNew {
static String accessTokenStr ="********************************";
static String accessTokenSecretStr ="********************************";
static String consumerKeyStr = "********************************";
static String consumerSecretStr ="********************************";
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public static void main(String[] args) {
try{
String url="https://api.twitter.com/1.1/users/search.json?q=sony&count=2";
OAuthConsumer oAuthConsumer = new CommonsHttpOAuthConsumer(consumerKeyStr,
consumerSecretStr);
oAuthConsumer.setTokenWithSecret(accessTokenStr, accessTokenSecretStr);
// oAuthConsumer.
HttpGet httpPost = new HttpGet(url);
oAuthConsumer.sign(httpPost);
//oAuthConsumer.//
System.out.println("the url is for request "+httpPost.getURI());
HttpClient httpClient = new DefaultHttpClient();
HttpResponse httpResponse = httpClient.execute(httpPost);
//
System.out.println(IOUtils.toString(httpResponse.getEntity().getContent()));
BufferedReader streamReader = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent(), "UTF-8"));
StringBuilder responseStrBuilder = new StringBuilder();
String inputStr;
while ((inputStr = streamReader.readLine()) != null)
responseStrBuilder.append(inputStr);
System.out.println(""+responseStrBuilder.toString());
JSONArray responseJson=new JSONArray(responseStrBuilder.toString());
System.out.println("The Content is TwitterJson text is "+responseJson);
JSONObject TwitterJson=responseJson.getJSONObject(0);
System.out.println("The Content is TwitterJson text is "+TwitterJson);
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JSONObject recenttweetJson=TwitterJson.getJSONObject("status");
JSONObject entities=recenttweetJson.getJSONObject("entities");
JSONArray media=entities.getJSONArray("media");
JSONObject subMedia=media.getJSONObject(0);
String urlHttps=subMedia.getString("media_url_https");
String urlHttp=subMedia.getString("media_url");
long id=recenttweetJson.getLong("id");
/*media_url_https*/
HttpGet httpget=new HttpGet(urlHttps);
HttpClient httpClient2 = new DefaultHttpClient();
HttpResponse httpResponse2 = httpClient2.execute(httpget);
int statusCode = httpResponse2.getStatusLine().getStatusCode();
System.out.println("The status code og image url is"+statusCode);
if(statusCode==200){
Image image = null;
URL surl = new URL(urlHttps);
image = ImageIO.read(surl);
JFrame frame = new JFrame();
frame.setSize(300, 300);
JLabel label = new JLabel(new ImageIcon(image));
frame.add(label);
frame.setVisible(true);
}
}catch(Exception e){
System.out.println("Exception in TIWTTER API");
e.printStackTrace();
}
}
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protected static String getTimestampFromLocalTime(Date date) {
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");
format.setTimeZone(TimeZone.getTimeZone("GMT"));
return format.format(date);
}
}
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Response:
{“errors”:[{“message”:“Your credentials do not allow access to this resource”,“code”:220}]}
How to use the API with out any interrupts ,Suggest Me
