How to create an app without mobile #

[nk06iitkgp]

I totally agree. I can’t add twitter login to my site. I could’t add my mobile as it says your service provider not available. It’s annoying. What is the point in including it if you don’t have access to all mobile service provider. I didn’t face these issues with facebook and google.

[Postatic]

this is obviously not thought out properly. I selected the right carrier, and entered my phone number and it says “text GO to this number”. So I texted “GO” to that number and my phone says “message cannot be delivered”.

[VikenEmesh]

Having the same problem here. German carrier E-Plus is not supported, so I can’t test out the API for work. We would’ve wanted to integrate Twitter in our software, but I guess we’re out of luck.

[froginthevalley]

Thanks for all the comments, keep 'em coming, we are reading all of them and are evaluating options.

[winetimesco]

Hi
I need to setup twitter apps for a few different client, but I only have 1 phone number. And to top it off, none of our national carriers are supported. Very frustrating.

[obenlink]

To add to you considerations: I am abroad and my carrier disabled roaming (so I cannot use the long code) plus my carrier does not seem to be supported which means I can not create an app until I am back. This is inconvenient.

[lesbonsoutils]

Me, too! same problem haizzz

[pervers_gefragt]

Me, too! same problem

[CsiroDave]

@froginthevalley this is a very short-sighted change that has inconvenienced a lot of people. How did the team who came up with it not realise that you didn’t have 100% coverage of mobile phone providers, and probably never will?

Two weeks seems like a long time to wait for a fix.

I can only guess this was put in place to stop people from creating lots of developer accounts to circumvent rate limits. A simpler way to do that would be to require a valid credit card (that you never bill). I’ve seen this tactic used by Google to regulate access to free APIs like Google Places.

[Taufik_Hidayaat]

walla, i have same problem sir. but I still can get Mobile Verification. but. when i try make app. i get this notice:
“Error
We protect against potentially abusive behavior. Your request has been rejected for now. Please try again later or contact Platform Operations through https://support.twitter.com/forms/platform”

I never make app in this account before.

[VerzekeringWeb]

I have the same problem. Added phone to another account yesterday with longcode (wich was extremely expensive! I want my money back!!) and now I can’t create an app under this account because I cannot connect my phone to this account too.

[maxigramar]

We also have the same problem.
We will have a solution?
Thanks

[unfi_v]

Same here… I’ve spend 3 dollars trying to go through long-number registration, but have failed. Guys from support tell me nothing useful. So, it appears that none of my apps going to have Twitter integrated.

[orios2000]

Bonjour,
je voudrais créer une application. J’ai remplis le formulaire (nom, description, site), lors de la validation on me demande de rajouter un numéro mobile. Je mets mon numéro et mon opérateur listé correctement sur paramètre. Twitter me dit qu’il ne peut pas communiquer avec lui et qu’il y a une erreur pour envoyer le numéro PIN. Je réessaie plusieurs fois mais sans succès. J’ai même essayé de le faire via le long code UK et Germany car je n’ai pas trouvé de short code pour la France mais rien encore une fois. Trouvez nous une solution please!!!
Cordialement

[mhsorens]

It’s quite frustrating, that after having tried all and every instruction provided by Twitter and requesting support according to the entry by @froginthevalley, you get referred back to exactly the same procedures, you’re unable to complete.

[heregearttest]

Hey everybody - here’s some food for thought: maybe Twitter is actually trying to help us all out here…um, can you say Eddie Snowden? Maybe they’re pissed at the NSA… It makes me happy to think that all those spies are having to head to Radio Shack and 7-11 to buy non-traceable phones.

Of course, Q-Branch probably has an app that does that, right?

And that’s the biggest problem I see w/this: just go unlock a droid, throw a pay-as-you-go over-the-counter SIM in it - and make as many accounts as you want - and you’ve just circumvented this new Twitter requirement.

[adromil]

this is not true! I tried it just now and also use a mobile number from my another twitter account and it works seamlessly.

[appDelegate.hudAlert show]; if (!self.imageView.image) { [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES]; [[[UIAlertView alloc] initWithTitle:@"No Picture to Post" message:@"Please Take a Photo or Select a Photo to continue." delegate:self cancelButtonTitle:@"Ok" otherButtonTitles:nil] show];

} else {
    ACAccountStore *twitterAcct = [[ACAccountStore alloc] init];
    ACAccountType *twitterAcctType = [twitterAcct accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];
    
    [twitterAcct requestAccessToAccountsWithType:twitterAcctType withCompletionHandler:^(BOOL granted, NSError *error) {
        NSLog(@"Request to Update to Twitter");
        if (granted == YES) {
            // Populate array with all available Twitter accounts
            NSArray *arrayOfAccounts = [twitterAcct accountsWithAccountType:twitterAcctType];
            
            // Sanity check
            if ([arrayOfAccounts count] > 0) {
                
                // Keep it simple, use the first account available
                ACAccount *acct = [arrayOfAccounts objectAtIndex:0];
                NSLog(@"Twitter Account: %@", acct);
                
                NSURL *postURL = [NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/update_with_media.json"];
                
                NSDictionary *params = @{@"status": [NSString stringWithFormat:@"took a #selfie via %@", self.appName]};
                
                SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodPOST URL:postURL parameters:params];
                
                NSData *imageData = UIImagePNGRepresentation(self.imageView.image);
                
                [request addMultipartData:imageData withName:@"media[]" type:@"image/png" filename:nil];
                
                [request setAccount:acct];
                [request performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {
                    //                          NSLog(@"Twitter response, HTTP response: %i", [urlResponse statusCode]);
                    NSLog(@"Twitter response: %@, HTTP response: %@", responseData, urlResponse);
                    
                    if (responseData) {
                        NSInteger statusCode = urlResponse.statusCode;
                        if (statusCode >= 200 && statusCode < 300) {
                            NSError *jsonError;
                            NSDictionary *twitterResponse = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableContainers error:&jsonError];
                            //                        NSLog(@"Created Tweet with ID: %@", postResponseData[@"id_str"]);
                            NSLog(@"postResponseData: %@", twitterResponse);
                            
                            if (twitterResponse) {
                                [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
                                NSLog(@"Timeline Response: %@\n", twitterResponse);
                                [[[UIAlertView alloc] initWithTitle:@"Photo Uploaded" message:@"Check your Twitter profile to see the upload." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
                            } else {
                                [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
                                // Our JSON deserialization went awry
                                NSLog(@"JSON Error: %@", [jsonError localizedDescription]);
                            }
                        }
                        else {
                            [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
                            NSLog(@"Server Error: [%d] %@", statusCode,
                                  [NSHTTPURLResponse localizedStringForStatusCode:statusCode]);
                        }
                    } else {
                        [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
                        NSLog(@"Mga SINUNGALING kayo! Mga PUTANGINA ninyo");
                    }
                    
                }];
            } else {
                [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
                NSLog(@"No Accounts found.");
            }
            
        } else {
            [appDelegate.hudAlert dismissWithClickedButtonIndex:0 animated:YES];
            [[[UIAlertView alloc] initWithTitle:@"Unable to Upload Photo" message:@"You Have Not Granted This App to Upload Photo on Your Behalf" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil] show];
        }
        
    }];
}

mga GUNG-GONG

[adromil]

For JAVA / Android:

import twitter4j.Status; import twitter4j.Twitter; import twitter4j.TwitterException; import twitter4j.TwitterFactory; import twitter4j.auth.AccessToken; import twitter4j.auth.OAuthAuthorization; import twitter4j.auth.RequestToken; import twitter4j.User;

import twitter4j.conf.Configuration;
import twitter4j.conf.ConfigurationBuilder;
import twitter4j.media.ImageUpload;
import twitter4j.media.ImageUploadFactory;
import twitter4j.media.MediaProvider;

import java.io.File;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public final class PostWithImage {

/**
 * Developer : Waqas Ghouri
 * Email     : waqas_ghouri89@hotmail.com
 * @param args message
 */
public static void main(String[] args) throws TwitterException {

    String UserAccessToken = null;
    String UserAccessSecret = null;

    try {

        Twitter twitter = new TwitterFactory().getInstance();


         //Set Your Application Consumer Key & Consumer Key Secret
         twitter.setOAuthConsumer("xxxxxxxxxxxx","xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx");

        try {
            // get request token.
            // this will throw IllegalStateException if access token is already available
            RequestToken requestToken = twitter.getOAuthRequestToken();
            System.out.println("Got request token.");
            System.out.println("Request token: " + requestToken.getToken());
            System.out.println("Request token secret: " + requestToken.getTokenSecret());


            AccessToken accessToken = null;


            // to check this example set you callback URL to empty. If your application 
            // callback URL is defined then URL generated by below code should be redirected
            // to callback URL, so when we set callback URL to empty it shows PIN CODE to access OAUTH

            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
            while (null == accessToken) {
                System.out.println("Open the following URL and grant access to your account:");
                System.out.println(requestToken.getAuthorizationURL());
                System.out.print("Enter the PIN(if available) and hit enter after you granted access.[PIN]:");
                String pin = br.readLine();
                try {
                    if (pin.length() > 0) {
                        accessToken = twitter.getOAuthAccessToken(requestToken, pin);
                    } else {
                        accessToken = twitter.getOAuthAccessToken(requestToken);
                    }
                } catch (TwitterException te) {
                    if (401 == te.getStatusCode()) {
                        System.out.println("Unable to get the access token.");
                    } else {
                        te.printStackTrace();
                    }
                }
            }
            System.out.println("Got access token.");
            UserAccessToken = accessToken.getToken();
            UserAccessSecret = accessToken.getTokenSecret();
            System.out.println("Access token: " + UserAccessToken);
            System.out.println("Access token secret: " + UserAccessSecret);


        } catch (IllegalStateException ie) {
            // access token is already available, or consumer key/secret is not set.
            if (!twitter.getAuthorization().isEnabled()) {
                System.out.println("OAuth consumer key/secret is not set.");
                System.exit(-1);
            }
        }

        //Fetching User Information
        //User Information from twitter.
        System.out.println("Connecting.... ");
        System.out.println("Twitter Connected To : ");

        User user = twitter.showUser(twitter.getId());
        System.out.print(user.getScreenName());
        if (user.getStatus() != null) {
            System.out.println("@" + user.getScreenName() + " - " + user.getStatus().getText());
        } else {
            // the user is protected
            System.out.println("@" + user.getScreenName());
        }


        // If you want simple post on status uncomment below code

        //System.out.println("Trying to simple post");      
        //Status status = twitter.updateStatus("Normal Post on Twitter Statsus");


        // Below code post with image and message           
        System.out.println("Now Try to upload Image");


        // Specify the image path in you system ( windows / unix / mac what ever)
        // ex(windows) : C:\imagepost.png
                // ex(linux)   : /home/waqas/imagepost.png  
        String ImagePath = null;
        br = new BufferedReader(new InputStreamReader(System.in));
        while (null == ImagePath) {
            System.out.println("Please Type Image Path: ");
            String path = br.readLine();
            if (path.length() > 0) {
                ImagePath = path;
            } else {
                path = "";
                System.exit(-1);
            }
        }


        // type your message(status)
        String Message = null;
        br = new BufferedReader(new InputStreamReader(System.in));
        while (null == Message) {
            System.out.println("Please type your message: ");
            String msg = br.readLine();
            if (msg.length() > 0) {
                Message = msg;
            } else {
                Message = "";
                System.exit(-1);
            }
        }


         try {

                Configuration conf = new ConfigurationBuilder()
                                    .setOAuthConsumerKey("iNTvDz04pKChDYH6yON1iA")
                                    .setOAuthConsumerSecret("8SBdm5Vwme9jMGpgYCxLjbfVLH2geWpmGNltPyTaM")
                                    .setOAuthAccessToken(UserAccessToken)
                                    .setOAuthAccessTokenSecret(UserAccessSecret).build();


                OAuthAuthorization auth = new OAuthAuthorization(conf);
                ImageUpload upload = new ImageUploadFactory(conf).getInstance(auth);

                String url;
                if (ImagePath.length()>0) {
                    url = upload.upload(new File(ImagePath), Message);
                } else {
                    url = upload.upload(Message,null);
                }
                System.out.println("Successfully uploaded image to Twitpic at " + url);
                System.exit(0);
            } catch (TwitterException te) {
                te.printStackTrace();
                System.out.println("Failed to upload the image: " + te.getMessage());
                System.exit(-1);
            }

        System.exit(0);


    } catch (TwitterException te) {
        //te.printStackTrace();
        System.out.println("Failed to get timeline: " + te.getMessage());
        System.exit(-1);
    } catch (IOException ioe) {
        ioe.printStackTrace();
        System.out.println("Failed to read the system input.");
        System.exit(-1);
    }
}

}

[misiak_dady]

Hi folks!
I also got a message “Sorry, we don’t have a connection to your carrier yet!” when trying to register new app. So I added my phone via long code solution (UK number) and it worked for me. I can now create an app.
Hope this helps.

[whiteboomerangd]

I agree to the earlier comments that a phone number shouldn’t be necessary for creating an app. After dozens of text messages and 24 hour waiting we finally could link our phone, so in addition even the process doesn’t work well.